54. Population Count

How do you plan to solve it?

simply using a for loop, can also be done using full adders per 3 bits : adding the results to finally get the no of 1's

module popcount8 (
    input  [7:0] in,
    output reg [3:0] count
);
    integer i; // loop variable must be declared (synthesizable)
    always @* begin
        count = 4'd0;          // default to avoid latch

        // Use a for-loop to accumulate the number of '1' bits
        for (i = 0; i < 8; i = i + 1) begin
        // Write code here
            count = (in[i]) ? count + 1 : count;  // count = count + in[i];

        end
    end
endmodule
// can also be done using full adders