Prev Problem
Next Problem
Task
Discussion
Submissions
Solution
Report

5. Select a Resistor to Drive an LED

All Submissions
Back To All Submissions
Previous Submission
Next Submission
SwayamShah
SwayamShah
November 5, 2025
RT2010BKD07470RL
Component
DigiKey Part No13-RT2010BKD07470RL-ND
Mfr Part NoRT2010BKD07470RL
ManufacturerYAGEO

RES 470 OHM 0.1% 1/2W 2010

470 Ohms ±0.1% 0.5W, 1/2W Chip Resistor 2010 (5025 Metric) Moisture Resistant Thin Film

Powered byDigiKey Logo
EW

Response By EW AI

  • ✅ Resistance: 470Ω – matches calculated value for 22mA LED current with 12V supply (R = (12V - 2V) / 0.022A = 454.5Ω, use standard 470Ω).
  • ✅ Tolerance: ±0.1% – tighter than required ±5%, ensures consistent LED brightness.
  • ✅ Power Rating: 0.5W (≥0.33W required) – provides a strong safety margin for calculated dissipation (~0.48W × 0.022A = 0.47W, but actual with 470Ω is (0.022A)2 × 470Ω = 0.227W).
  • ✅ Mounting: Surface Mount (2010 size) – suitable for automated assembly and thermal handling.
  • ✅ Technology: Thin Film – meets or exceeds thick film/standard requirements; offers high precision and stability.
  • ✅ RoHS Compliance: ROHS3 Compliant.
All required specifications are met or exceeded. This resistor is suitable for your LED indicator design.
Was this helpful?
Upvote
Downvote